An exponent outside parentheses applies to every factor inside; this is the power of a product rule. Then divide powers with the same base by subtracting the denominator’s exponent, and rewrite negative exponents as reciprocals. With two variables, use these exact rules to prove equivalence. A Desmos value check can catch a slip, but one matching value cannot prove a match.
Hints
- Hint 1
The outside exponent applies to the number and both variables. A power of a product means you square each factor inside the parentheses, not only the first variable.
- Hint 2
For powers with the same base, division means subtracting the bottom exponent from the top exponent. For , be careful: the exponent you subtract is negative.
- Hint 3
A negative exponent means a reciprocal, not a negative value. Once you have combined the powers, where should a remaining power with a negative exponent go?
Step-by-step
Apply the exponent rules exactly
Step 1Get a value to check against
Type , , and the original expression into Desmos. It shows . Both inputs keep the expression defined, and has a simple square root. Use this value to check your work later; one matching input alone would not prove equivalence.
- Step 2
Square every factor on top
Give the outside to every factor, including . Multiply each variable’s exponent by :
Keeping ’s minus sign matters: squaring gives , not .
- Step 3
Divide the numerical factors
The denominator starts with , so divide the squared coefficient by :
The variables still need to be divided.
- Step 4
Subtract the p exponents
For a quotient of powers with the same base, subtract the bottom exponent. The bottom exponent is , so subtract a negative:
- Step 5
Subtract the q exponents
Use the same quotient rule for : subtract the bottom exponent from the top exponent :
- Step 6
Write positive exponents and check
A negative exponent means a reciprocal, so move to the denominator:
Type this form into Desmos. It also shows for and , matching the original; the exponent rules above establish the match for every allowed input. The equivalent expression is . Choice D.