Question 56·Easy·Advanced Math

Type $3(x-2)^2+y=5$ in Desmos. Its graph falls on either side of $x=2$. As $(x-2)^2$ grows, $y$ must shrink to keep the sum at $5$, so expect a negative squared term when $y$ is alone.

To leave $y$ alone, subtract the entire $3(x-2)^2$ from both sides, not $x-2$ by itself:

Cancel the opposite copies of $3(x-2)^2$ on the left: $y=5-3(x-2)^2$. The negative squared term matches the falling graph, and $y$ is now in terms of $x$. Choice D.