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The equation above relates the distinct real numbers sss and ttt with 2t+3≠02t + 3 \neq 02t+3=0. Which equation correctly expresses ttt in terms of sss?
t=5s−22−3st = \frac{5s - 2}{2 - 3s}t=2−3s5s−2
t=1−3s5+2st = \frac{1 - 3s}{5 + 2s}t=5+2s1−3s
t=1+3s2s−5t = \frac{1 + 3s}{2s - 5}t=2s−51+3s
t=1+3s5−2st = \frac{1 + 3s}{5 - 2s}t=5−2s1+3s
