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The relationship z=3(y−2)2z = 3(y - 2)^2z=3(y−2)2 holds for real numbers yyy and zzz. If y≥2y \ge 2y≥2, which equation correctly expresses yyy in terms of zzz?
y=2−z3y = 2 - \sqrt{\dfrac{z}{3}}y=2−3z
y=3z+2y = \sqrt{3z} + 2y=3z+2
y=z3+2y = \dfrac{\sqrt{z}}{3} + 2y=3z+2
y=2+z3y = 2 + \sqrt{\dfrac{z}{3}}y=2+3z
