Both equations involve the same quantity $\left(\frac{2}{3}p\right)$. Consider dividing one equation by the other to cancel it.

You should get an equation of the form $\frac{96}{80}=\frac{p}{p-20}$. Cross-multiply to solve for $p$. Тhіѕ ques​t‌іo‌n is from‍ ‍Aniko

Let $x$ represent $p$. Enter ЅA‌T​ prep by ‍Аnікο‍.аi

• $y=96$
• $y=(x/100)\cdot(2/3)\cdot x$

Enter

• $y=80$
• $y=((x-20)/100)\cdot(2/3)\cdot x$

Find the $x$-value(s) where the first pair intersects and the $x$-value(s) where the second pair intersects. The value of $p$ must satisfy both equations and also $x>20$. Match that $x$-value to the answer choices.

Convert each percent to a fraction: (Аnікo.aі‌)

Divide the first equation by the second. The factor $\left(\frac{2}{3}p\right)$ and the $\frac{1}{100}$ cancel:

Simplify:

Cross-multiply:

Since $p>20$, the solution is valid. The correct choice is 120.