If the 2023 amounts are $a$ and $b$, write one equation for the 2024 total using both the individual changes and the 6% total increase.

The 2025 changes are based on the 2024 amounts, not directly on the 2023 amounts. Apply each new multiplier to the appropriate 2024 expression.

Algebra is faster because the 2024 total condition first gives the relationship $a=1.5b$ between the 2023 process amounts.

After substituting $a=1.5b$ into the 2025 total, enter $y=2.64x$ and $y=10560$. Click their intersection. The $x$-coordinate represents the 2023 electricity use for Process B.

Let $a$ be the electricity used for Process A in 2023 and let $b$ be the electricity used for Process B in 2023.

In 2024, the two process amounts were $1.2a$ and $0.85b$. Because the total was 6% greater than the 2023 total, $1.2a+0.85b=1.06a+1.06b$.

Subtracting gives $0.14a=0.21b$, so $a=1.5b$.

The 2025 amount for Process A was $0.9(1.2a)=1.08a$, and the 2025 amount for Process B was $1.2(0.85b)=1.02b$.

Thus, $1.08a+1.02b=10{,}560$. Substitute $a=1.5b$:

$1.08(1.5b)+1.02b=10{,}560$

$2.64b=10{,}560$, so $b=4000$.