Analyze changed data and outliers

Lesson progressPractice problems 0/3
Difficulty
Intermediate
Estimated time
27 minutes
Techniques
Changed-dataOutliersMean-sensitivityMedian-positionSpread-effects

What you’ll learn

  1. Spot when a question changes only some of the values, by adding, removing, correcting or replacing them.
  2. Tell how the change affects the total and the mean.
  3. Put the new data in order before deciding what happens to the median.
  4. Check whether the smallest or largest value changed before deciding what happens to the range.
  5. Compare distances from the mean before deciding what happens to standard deviation.

Why this matters on the SAT

Give each statistic its own test

An SAT question might fix a value that was recorded wrong, add an outlier (a value far from the rest), drop the smallest or largest value, or swap a few values for new ones. Then it asks what happened to the mean, median, range or standard deviation. The catch is that one change can move some of them and leave others exactly where they were.

Solution to the example

Swapping 4545 for 2424 lowers the total by

45−24=21.45-24=21.

There are still 77 values, so the mean goes down.

Now the median. In both ordered lists, 1515 sits in the fourth spot, right in the middle:

X:11, 13, 14, 15, 16, 18, 45,Y:11, 13, 14, 15, 16, 18, 24.\begin{aligned} X&: 11,\ 13,\ 14,\ \boxed{15},\ 16,\ 18,\ 45,\\[1.4em] Y&: 11,\ 13,\ 14,\ \boxed{15},\ 16,\ 18,\ 24. \end{aligned}

So the medians are equal. The answer is A.

The big value moved the mean because the mean adds up every value. It didn’t move the median, because the new value, 2424, still sits to the right of the middle.

SAT example

Data set XX consists of the values

11, 13, 14, 15, 16, 18, 45.11,\ 13,\ 14,\ 15,\ 16,\ 18,\ 45.

Data set YY is created by replacing 4545 with 2424. Which statement correctly compares the means and medians of the two data sets?

  1. A

    The mean of YY is less than the mean of XX, and the medians are equal.

  2. B

    The mean and median of YY are both less than those of XX.

  3. C

    The means are equal, and the median of YY is less than the median of XX.

  4. D

    The means and medians are equal.

Spot when only some values change

These questions give you a data set, then change part of it and ask you to compare the two versions. The change might:

  • add one or more values
  • remove one or more values
  • correct a value that was recorded wrong
  • replace some values with new ones

Don’t reach for a whole-set shortcut unless the same rule hits every value, like adding 55 to each one. Those shifts and scales are covered in Reason with range and standard deviation. And if a question gives two means and asks only for a missing or removed value, that’s total-over-count arithmetic, covered in Recover totals and weighted means.

When only some values change, ask four separate questions, one for each statistic. In short: total, middle, ends, distances.

Four questions for a changed data set

StatisticWhat to watchQuestion to ask
MeanThe total and the countDid the change push the total up or down, or change the count?
MedianThe middle value, or the two middle valuesOnce the new list is in order, what sits in the middle?
RangeThe smallest and largest valuesDid either end change?
Standard deviationHow far values sit from the meanDid the values pull in closer to their mean or spread farther out?
Common mistake:

A bigger replacement doesn’t make every statistic bigger. Ask the four questions one at a time. A single change can lower the mean, leave the median alone and shrink the range, all at once, as the opening example did.

Track the mean through the total

Think of the mean as a fair share: the total split evenly across all the values. So a change to some of the values can move the mean in only two ways, by changing the total or by changing the count.

Replace or correct a value

Say one value aa is replaced by bb, and there are still nn values. Then

new total=old total−a+b.\text{new total}=\text{old total}-a+b.

The mean changes by

new mean−old mean=b−an.\text{new mean}-\text{old mean}=\frac{b-a}{n}.

So a larger replacement raises the mean, and a smaller one lowers it. The mean moves toward the new value, because that value changes the total everyone shares. In the opening example, b−a=24−45=−21b-a=24-45=-21 and n=7n=7, so the mean dropped by 33.

Add a value

Compare the new value with the old mean:

  • A value above the old mean raises the mean.
  • A value below the old mean lowers the mean.
  • A value equal to the old mean leaves the mean the same.

The new mean lands somewhere between the old mean and the added value. A value far from the rest can pull the mean a lot, since its full size goes into the total.

Remove a value

Removing works the other way around:

  • Removing a value above the old mean lowers the mean.
  • Removing a value below the old mean raises the mean.
  • Removing a value equal to the old mean leaves the mean the same.
Check your understanding:

A data set has a mean of 1818. Without calculating a new mean, what happens if a value of 4242 is added? What happens instead if an existing value of 4242 is removed?

Reorder before deciding the median

The median depends on position in the ordered list, not on the total. An extreme value can change a lot and still stay on the same side of the middle. When that happens, the median doesn’t move.

That’s where the saying “outliers don’t affect the median” comes from, and it’s only half true. This is the part that trips people up. Adding or removing a value changes the count, so the middle spot itself moves. And a replacement that crosses to the other side of the middle can change which value sits there.

Here’s a crossing. Start with

4, 6, 6, 8, 9, 11, 30.4,\ 6,\ 6,\ 8,\ 9,\ 11,\ 30.

The median is the fourth value, 88. Now replace 3030 with 55 and put the list back in order:

4, 5, 6, 6, 8, 9, 11.4,\ 5,\ 6,\ 6,\ 8,\ 9,\ 11.

The new median is 66. It went down because 55 jumped from the far right to the left of the old middle.

Common mistake:

The median holds steady through many extreme changes, but it isn’t frozen. Write the new list in order, count the values again, and find the new middle value, or the two middle values.

Check your understanding:

The ordered data are 6,8,9,10,12,15,346,8,9,10,12,15,34. The value 3434 is removed. What happens to the mean, median, and range?

See how a change affects spread

Range and standard deviation both measure spread, but they look at different things.

  • The range looks only at the two ends, so it changes only when the smallest value, the largest value, or both change.
  • Standard deviation looks at how far the values typically sit from the mean, so it changes when those distances change.

The dot plots below show the same nine values before and after two swaps: 22 becomes 77, and 1818 becomes 1313.

The two swaps keep the mean at 10 but shrink both the range and the typical distance from the mean.

Start with the mean. The two values that left add up to

2+18=20,2+18=20,

and the two that replaced them add up to

7+13=20.7+13=20.

Same total, same count, so the mean stays 1010. The median stays 1010 too.

Now the range. The ends change from 22 and 1818 to 44 and 1616, so the range shrinks:

16⟶12.16 \longrightarrow 12.

Last, standard deviation. Check how far each swapped value sits from the mean, before and after:

∣2−10∣=∣18−10∣=8,∣7−10∣=∣13−10∣=3.\begin{aligned} |2-10|=|18-10|&=8,\\[1.4em] |7-10|=|13-10|&=3. \end{aligned}

Only those two values changed, and both moved closer to the same mean. So the standard deviation goes down.

This distance check is cleanest when the mean stays put. If the mean moves too, every value gets a new point to measure from, not just the swapped ones. So when some changes pull in and others push out, or the comparison is close, look at the whole new data set, or check it with a calculator list you’ve verified, instead of judging one value on its own.

Check your understanding:

A data set has minimum 00, maximum 1010, and mean 55. Two values in between, 22 and 88, are replaced by 44 and 66. What happens to the range and standard deviation?

Example: Same mean, smaller spread

When values get swapped, check their totals before their distances. Here’s why the order matters.

Worked example

Data set A consists of 1111 values and has a mean of 2020. Two of its values are 88 and 3232.

Data set B is created by replacing 88 and 3232 with 1414 and 2626, respectively. All other values remain unchanged.

Which statement correctly compares the mean and standard deviation of data set B with those of data set A?

  1. A

    The mean of B is greater than the mean of A, and the standard deviations are equal.

  2. B

    The mean of B is equal to the mean of A, and the standard deviation of B is greater than the standard deviation of A.

  3. C

    The mean of B is equal to the mean of A, and the standard deviation of B is less than the standard deviation of A.

  4. D

    The mean and standard deviation of B are both less than those of data set A.

Step 1

Add up each pair

The two values that leave add up to

8+32=40.8+32=40.

The two that come in also add up to

14+26=40.14+26=40.

Nothing is added or removed, so the total and the count stay the same, and the mean stays 2020.

Step 2

Measure distances from the same mean

The old values are each 1212 units from 2020:

20−8=12and32−20=12.20-8=12 \quad\text{and}\quad 32-20=12.

The new values are each 66 units from 2020:

20−14=6and26−20=6.20-14=6 \quad\text{and}\quad 26-20=6.

Every other value stays put, so its distance doesn’t change. The new data set sits closer around the same mean, so the standard deviation goes down.

Step 3

Match both results

The mean stays the same, and the standard deviation gets smaller. The answer is C.

Check your understanding:

Why did you need to know the mean stayed the same before comparing the distances?

Common mistake:

Standard deviation isn’t set by how far apart two values are from each other. Find the mean first. Then check how far each changed value sits from that mean, and remember that the rest of the data counts too.

Reason first, then check with a calculator

You’ll usually do these by hand. The hard part isn’t the arithmetic. It’s knowing which feature controls each statistic. So mark exactly which values were added, removed, corrected or replaced, then ask the four questions: total, middle, ends, distances.

For a long, unordered list, a Desmos list can check your work:

  • Type the original data once as A=[...].
  • Type the complete revised data as B=[...].
  • Check every entry against the question.
  • Look at mean(A), median(A), mean(B) and median(B) as you need them.
  • Use stdevp(A) and stdevp(B) only when the standard deviation comparison isn’t already clear.

The list checks your answer. It doesn’t replace the reasoning. Desmos can calculate two statistics, but it can’t tell you why an unchanged end keeps the range the same, or why crossing the middle moves the median.

Common mistake:

Adding a value gives you one more entry, but replacing a value keeps the count the same. Before you trust the calculator, check both the entries and the length of the list against the question.

Practice problems

Each problem makes a different kind of change: first a corrected entry, then an added outlier, then a swap that keeps the total.

Fix an extreme entry

Practice problem

The recorded finish times, in minutes, for seven runners were

42, 44, 45, 47, 48, 50, 81.42,\ 44,\ 45,\ 47,\ 48,\ 50,\ 81.

The recorded time of 8181 minutes was a data-entry error. The actual time was 5151 minutes. Which statement correctly describes the corrected data set compared with the recorded data set?

Answer choices
Calculator loads as you approach
Work out the total, the middle and the ends first. The calculator is here if you want to check.

Add a large value

Practice problem

A data set consists of the values

9, 11, 12, 13, 15.9,\ 11,\ 12,\ 13,\ 15.

The value 2727 is added to the data set. Which statement correctly describes the new data set?

Answer choices
Calculator loads as you approach
Compare the new value with the old mean, then recount the middle.

Same range, different spread

Practice problem

Data set A is

0, 2, 5, 5, 5, 8, 10.0,\ 2,\ 5,\ 5,\ 5,\ 8,\ 10.

Data set B is created by replacing 22 and 88 with 44 and 66, respectively. Which statement correctly compares the means, ranges, and standard deviations of the two data sets?

Answer choices
Calculator loads as you approach
Settle the total and the ends before you think about standard deviation.

Finish the lesson

3 practice examples left

Finish the remaining questions correctly to complete this lesson.

Quick recap

  • Give each statistic its own test. One change can move some statistics and leave others alone.
  • The mean follows the total and the count. An added value pulls the mean toward itself.
  • The median follows position. An extreme change may leave it alone, but a new count or a value crossing the middle can move it.
  • The range changes only when the smallest or largest value changes.
  • Standard deviation changes when the values spread out from their mean or pull in toward it.
  • If swapped values keep the same total, the mean stays put, and moving them closer to it lowers the standard deviation.
  • Reason it out first. Use a calculator list you’ve checked only for a long list or a close call.

Next lesson

Interpret scatterplots

Move from one-variable distributions to direction, strength, form, clusters, and outliers in paired data.

Start next lesson

Practice

Practice this lesson

146 SAT questions use what this lesson teaches. Practice a few in a study session at the difficulty you choose.

Start practice