Aniko

Solve one-variable equations

Lesson progressPractice problems 0/4

Solve linear and nonlinear SAT equations by graphing both sides in Desmos, finding every real solution, and submitting the quantity the question asks for.

Difficulty
Beginner
Estimated time
35 minutes

What you’ll learn

  1. Spot a question that gives you one equation with one unknown.
  2. Graph each side and find every real solution where the graphs meet.
  3. Type the whole equation on one line when that's quicker and still clear.
  4. Swap another letter, like zz, for xx without changing the equation.
  5. Pick the right solution when a question says positive, least, or greatest.
  6. Write one equation with one unknown for a total made of two kinds of things, like adult and student tickets.
  7. Finish the job by working out the value the question actually asks for.
  8. Tell when a quick solve by hand beats opening Desmos.

Why this matters on the SAT

Solve long equations without rearranging

SAT equations can bury a simple answer under fractions, parentheses, and several steps of algebra. When there's one unknown and the question asks for its value, Desmos can often find it without you rearranging anything.

SAT example

Which choice is the solution to the equation?

56(x−3)+4=13(x+6)+11\frac{5}{6}(x-3)+4=\frac{1}{3}(x+6)+11
Answer choices

Fast Desmos solution

Put each side on its own line in Desmos:

y=56(x−3)+4y=\frac{5}{6}(x-3)+4

and

y=13(x+6)+11.y=\frac{1}{3}(x+6)+11.

The graphs cross where x=23x=23. At that xx, the two sides are equal, so 2323 solves the equation, and the answer is C.

Here the answer was xx itself, but that isn't always so. The SAT might ask for the positive solution, the greater of two, or a value you build from the solution. So think of it as two jobs: solve, then answer the question.

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Where the graphs cross, x = 23 makes both sides equal.

When should you solve an equation in Desmos?

Desmos helps most when one unknown is buried in algebra that would take a while to untangle by hand.

Start with Desmos when…

  • There’s one unknown to find, even if it shows up in several places.

  • Fractions, parentheses, powers, or absolute values would slow the algebra down, as in 56(x−3)+4=13(x+6)+11\frac{5}{6}(x-3)+4=\frac{1}{3}(x+6)+11.

  • The equation might have more than one solution. (x+1)2=16(x+1)^2=16, for example, has two.

  • The question asks for one particular solution, such as the positive, negative, least, or greatest one.

  • The question asks for a value you work out from the solution, like x−4x-4.

Solve by hand when…

  • It takes a step or two. For x4+3=8\frac{x}{4}+3=8, subtract 33 and multiply by 44 to get x=20x=20.

The wording often gives these away, so read the question to the end before you start. “One possible solution,” for example, tells you the equation has more than one.

Check your understanding:

Which equation gives you a better reason to open Desmos: x+8=13x+8=13 or ∣3x−4∣=20\lvert 3x-4\rvert=20? What’s the difference?

Graph the two sides

A solution is a value of xx that makes the left side and the right side equal. So give each side its own graph. For an equation

L(x)=R(x),L(x)=R(x),

graph

y=L(x)y=L(x)

and

y=R(x).y=R(x).

Where the two graphs meet, the sides have the same value. So the x-coordinate of that meeting point, the intersection, solves the equation.

Try it with

5(x−4)+7=3(x+2)+5.5(x-4)+7=3(x+2)+5.

Enter

y=5(x−4)+7y=5(x-4)+7

and

y=3(x+2)+5.y=3(x+2)+5.

The graphs meet at (12,47)(12,47), so the solution is x=12x=12.

Try it yourself:

Change the last +5+5 on the right side to +9+9. Will the intersection move left or right? Make your guess, then click the new point to check.

Check your understanding:

The graphs above meet at (12,47)(12,47). Which coordinate solves the equation, and what does the other one tell you?

Your equation has only one unknown, xx. The yy is a helper Desmos uses to compare the two sides. (When yy is also an unknown in the original problem, you're solving a system of two equations.)

Replace other variable letters with x

Desmos uses lowercase xx as the variable on its horizontal axis. So if your equation uses a different letter, swap every copy of that letter for xx.

Take

3z+8=29.3z+8=29.

Swap zz for xx:

3x+8=29.3x+8=29.

Then graph y=3x+8 and y=29. They meet where x=7x=7, so the original unknown is z=7z=7.

Common mistake:

It’s easy to swap only some of the letters. If tt shows up three times, all three have to become xx. Miss one, and you’re no longer graphing the same equation.

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Where the graphs meet, both sides share a y-value. The x-value is the solution.

Keep every solution

Some equations have more than one real solution, and graphing both sides shows you all of them. Take

∣2x+1∣=11.\lvert 2x+1\rvert=11.

Enter

y=∣2x+1∣y=\lvert 2x+1\rvert

and

y=11.y=11.

The equation is true wherever the two graphs have the same output, and that happens twice:

(−6,11)and(5,11).(-6,11)\qquad\text{and}\qquad(5,11).

So the solutions are the xx-coordinates:

x=−6andx=5.x=-6\qquad\text{and}\qquad x=5.
Try it yourself:

Before you click either point, guess how many times this V-shaped graph and the horizontal line will meet. Then change 1111 to 55. Will the two solutions move closer together or farther apart? Predict first, then look.

Here both points fit on the screen, but that won't always happen. A second intersection can sit outside the window. So before you decide you've found every solution, zoom out or drag the graph around. Find them all first, and only then let words like positive, least, or greatest pick one.

Careful with the other coordinate, too. The 1111 is the value both sides share, not a solution, so don't submit a yy-coordinate unless the question asks for it.

Check your understanding:

For ∣2x+1∣=11\lvert 2x+1\rvert=11, what’s the least solution, and which part of an intersection gives it?

Desmos labels points with decimals. When the question needs an exact answer, like a fraction or a radical, and Desmos shows a decimal that doesn't end, don't guess the exact form from the screen. Convert it to a fraction if Desmos gives a clear one, check an answer choice, or finish with algebra.

Questions that ask whether an equation has no solution, one solution, or infinitely many need extra care. You'll get to them later, in How many solutions?

Direct entry can be a shortcut

You can also type the whole equation on one line. This is direct entry. Type

∣2x+1∣=11\lvert 2x+1\rvert=11

and Desmos draws vertical lines at x=−6x=-6 and x=5x=5, the two solutions. That saves time when the lines are easy to click.

The two-graph method still gives the clearer picture, though. Stick with it when the equation might have several solutions, when the question asks you to compare them, when the shape of each side helps explain the answer, or when you want to see for yourself that the two sides are equal.

Whichever way you enter it, type the equation exactly as it's given. Don't cancel a variable factor or square both sides to make it easier to type. Changes like these can quietly remove a restriction or add solutions that don't work in the original equation.

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Each point where the graphs meet gives one solution: its x-coordinate.

Example: Solve first, then answer the question

Worked example

The greater solution to the equation

(x−3)2=5x−9(x-3)^2=5x-9

is xx. What is the value of 2x+12x+1?

Step 1

Spot the two jobs

This question has two jobs. First, find every solution. Then take the greater one and use it to work out 2x+12x+1. The solution itself isn't the answer.

Step 2

Graph both sides

Type y=(x-3)^2 and y=5x-9 on separate lines. The parabola and the line meet at

(2,1)and(9,36).(2,1)\qquad\text{and}\qquad(9,36).

Their x-coordinates are the two solutions:

x=2andx=9.x=2\qquad\text{and}\qquad x=9.
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Two intersections, two solutions. Read the x-coordinate of each.

Step 3

Pick the one the question wants

The question wants the greater solution. Between 22 and 99, that's

x=9.x=9.

Step 4

Work out what the question asks for

Now put 99 into 2x+12x+1:

2x+1=2(9)+1=19.2x+1=2(9)+1=19.

The answer is

19.\boxed{19}.

Common mistake: Submitting 99. It really is the greater solution, but the question asks for 2x+12x+1, so 99 gets you only halfway.

Turn a context into one equation

Some SAT questions describe a situation and leave the equation to you. The trick is to pick one unknown and write every quantity that changes in terms of it.

Say a venue sells nn tickets in all, and xx of them are adult tickets. The rest are student tickets, so there are

n−xn-x

of those. If adult tickets cost aa dollars and student tickets cost ss dollars, the money adds up to

ax+s(n−x)=total revenue.ax+s(n-x)=\text{total revenue}.

Once your equation includes every fact the question gives you, there's only one unknown left, and Desmos solves it the same way it solves any one-variable equation.

Check your understanding:

A center packs 6262 boxes in total. If xx is the number of large boxes, how would you write the number of small boxes?

Common mistake:

Using xx for both kinds of things, like adult and student tickets. If xx counts the adult tickets, it can’t also count the student tickets. Those are n−xn-x.

Finish the solution

We've already swapped zz for xx and graphed both sides. Click the point where they meet, then finish the question.

Finish the solution

The number zz is the solution to

3z+15−z−22=3.\frac{3z+1}{5}-\frac{z-2}{2}=3.

What is the value of z3\frac{z}{3}?

First steps

  1. Swap every zz for xx.
  2. Graph the left side and the right side on separate lines.
  3. Click the point where the graphs meet.

Finish it

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The x-coordinate where the graphs meet is the value of z.

Practice problems

Now it's your turn. Try each problem before you open its hint.

Practice problem

Which choice is the solution to the equation?

4(x+3)−5=2(x−1)+174(x+3)-5=2(x-1)+17
Answer choices
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Practice problem

What is the positive solution to the equation?

∣3x−2∣=16\lvert 3x-2\rvert=16
Answer choices
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Practice problem

A theater sold 8484 tickets for a performance. Adult tickets cost $18 each, and student tickets cost $11 each. The theater collected $1,204 from these tickets.

How many adult tickets were sold?

Answer choices
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Finish the lesson

4 practice examples left

Finish the remaining questions correctly to complete this lesson.

Quick recap

  • Graph each side of the equation on its own line. The x-coordinate where the graphs meet is a solution.
  • Direct entry, typing the whole equation on one line, is a quicker option when its vertical lines are easy to read.
  • If the equation uses another letter, swap every copy of it for xx.
  • Zoom out and find every solution before you let words like positive, least, or greatest pick one.
  • Solve, then answer the question. If it asks for 2x+12x+1 or a number of tickets, that's what you submit.
  • When a step or two by hand will do, skip Desmos.

Next lesson

Solve systems at intersections

Graph two equations with two original unknowns and read their shared solution point.

Start next lesson

Practice

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3,059 SAT questions use what this lesson teaches. Practice a few in a study session at the difficulty you choose.

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