Question 175·Easy·Equivalent Expressions
Which expression is equivalent to ?
When you see something like or, more generally, , immediately check if both terms are perfect squares so you can use the difference of squares pattern . Keep any coefficients outside the parentheses (like the 13 here) as they are, factor just the inside using the pattern, and then quickly eliminate wrong choices by expanding in your head or checking that the squared term and the constant match the original.
Hints
Look inside the parentheses first
Focus on . Can you rewrite as a square of something simpler?
Recognize a factoring pattern
Once you write as , what well-known pattern does look like?
Match the pattern carefully
Use with the correct choices of and , and then make sure the 13 in front is still there.
Desmos Guide
Enter the original expression
In one expression line, type 13(u^2 - 49v^2). Desmos will create sliders for u and v so you can assign them values.
Enter each answer choice as a separate expression
On new lines, type:
13(u - 7v)(u + 7v)13(u - 49v)(u + v)13(u - 7v)(u - 7v)13(u - 14v)(u + 14v)Desmos will show a numeric value for each once you set values foruandv.
Test several values of u and v
Move the sliders or type in values for u and v (for example, u = 2, v = 3, then u = -1, v = 4). For each pair of values, compare the numbers Desmos gives for the original expression and for each option. The expression that always matches the original for every tested pair is the equivalent one.
Step-by-step Explanation
Identify the structure inside the parentheses
Look at the part inside the 13: .
Notice that is a perfect square and is also a perfect square, because . So we can rewrite the expression as:
This is a difference of squares.
Recall the difference of squares formula
The standard factoring pattern for a difference of squares is:
Here, compare with :
- corresponds to .
- corresponds to .
Apply the formula and include the 13
Using and in the formula , we factor:
Now put back the 13 that was in front:
So the equivalent expression is .