When you see $-(x + 2)$, remember that the negative sign applies to both $x$ and $2$. How does that change the signs of each term?

After you simplify inside the brackets to something like $(\text{expression in } x)$, think of $- [\text{that expression}]$ as multiplying the inside by $-1$ before combining like terms.

Once everything is expanded and the brackets are gone, group $x$-terms together and constant terms together, then simplify.

In a new expression line, type 3(2x - 1) - (4(x - 3) - (x + 2)). Desmos will automatically simplify this expression; read the simplified form it shows (it should appear as 3x + 11), and then match that expression to the correct answer choice.

Start with the part $3(2x - 1)$. Distribute the 3 to both terms inside the parentheses:

So the whole expression becomes:

Now focus on the bracketed part $[4(x - 3) - (x + 2)]$.

First distribute the 4:

Now subtract $(x + 2)$, remembering the minus applies to both $x$ and $2$:

So the original expression is now:

You are subtracting the entire quantity $(3x - 14)$. Subtracting a group is the same as distributing $-1$ to each term inside:

Now you have an expression without brackets: $6x - 3 - 3x + 14$.

Combine the $x$-terms and the constant terms:

• $6x - 3x = 3x$
• $-3 + 14 = 11$

So the simplified expression is $3x + 11$.

Among the answer choices, this matches choice D, $3x + 11$.