A quadratic function can produce the same output at two different inputs. When a question asks which input gives a specified output, graph the function and a horizontal line at that output in Desmos, then click both intersections. Compare their x-coordinates with the answer choices by evaluating the radicals, rather than guessing from rounded graph labels.
Hints
- Hint 1
An input is an x-value, and the output is . To find an input that gives the requested output, set the whole function rule equal to that output. What horizontal line represents it on a graph?
- Hint 2
An intersection is a point shared by two graphs. At each crossing of the function and the target line, the x-coordinate is a possible input. Check both crossings because a quadratic can reach one height twice.
- Hint 3
Desmos labels intersections with rounded decimals, while the choices contain exact square roots. Evaluate each choice on its own Desmos line. Which decimal matches the x-coordinate of a crossing?
Step-by-step
Approach 1: Graph the target output
- Step 1
Turn the requested output into an equation
The question asks for an input whose output is , so set the entire rule equal to :
- Step 2
Find where the function reaches that output
Type and in Desmos. Click both intersections. Desmos shows approximately and . At an intersection, the x-coordinate is an input that gives the target output.
- Step 3
Match an exact choice to an intersection
Type the four radical choices on separate Desmos lines. In order, they display about , , , and . Only matches an intersection's x-coordinate, so it satisfies . Choice D.
Approach 2: Solve the squared equation exactly
- Step 1
Move the constant
Instead of reading decimals from the graph, start with . Subtract from both sides to isolate the squared term:
- Step 2
Remove the coefficient
Divide both sides by ; keep the negative sign with the coefficient:
- Step 3
Keep both square roots
Take square roots of both sides. A square has both a positive and a negative root, so keep both signs:
- Step 4
Simplify the radical
Because and , simplify the radical:
- Step 5
Find the listed input
Add to both sides: . The minus version is the listed value that gives . Choice D.