Question 9·Hard·Lines, Angles, and Triangles
Note: Figure not drawn to scale.
In the figure shown, and intersect at point . The angles at and are congruent (each marked ). , , , and . What is the length of ?
(Express the answer as an integer)
For geometry questions with intersecting lines and several given side lengths, first scan the diagram for marked equal angles and vertical angles at intersections; these usually signal similar triangles. Identify which triangles share those angles, then carefully match corresponding vertices (often via the equal angles) to pair up sides correctly. Set up a proportion using sides that are both known and adjacent to the equal angles, solve algebraically for the unknown side, and ignore extra lengths that do not fit into the similarity relationship.
Hints
Look for triangles that share the marked angles
Which two triangles in the figure each contain one of the angles marked at and , and also involve the given side lengths (35, 25, 56, and the unknown)? Focus on triangles that have vertices at , , and at , , .
Use the intersection at T
At point , lines and intersect and form vertical angles. Which angles in triangles and are vertical to each other, and what does that tell you about the relationship between the two triangles?
Set up a ratio of corresponding sides
Once you know the two triangles are similar, match the angle at with the angle at . Then compare the sides that touch those angles: use the sides of lengths 35 and 25 in one ratio, and match them with the sides of lengths 56 and the unknown length in another ratio.
Solve the equation you get
Your proportion should look like a fraction with 35 and 25 on one side and 56 and the unknown on the other. Solve this proportion for the unknown side length.
Desmos Guide
Write the equation for SN from similarity
From the similar triangles, you should have a proportion of the form , where represents the length of . Rearrange it to get .
Evaluate the expression in Desmos
In Desmos, type (25*56)/35 (or 56*25/35) and let Desmos compute the result. The value it outputs is the length of .
Step-by-step Explanation
Identify the key triangles
Focus on triangles and :
- Triangle includes the sides and , and has an angle at marked .
- Triangle includes the sides and (the unknown), and has an angle at also marked .
These are the two non-right triangles that involve all the given side lengths and the marked angles.
Use the angle information to show similarity
Because the angles at and at are both marked , we know
- in triangle equals in triangle .
Also, lines and intersect at , so the angle in triangle and the angle in triangle are vertical angles, which are congruent.
With two pairs of equal angles, triangles and are similar by the angle-angle (AA) criterion.
Match corresponding vertices and set up a proportion
From the similarity, we match vertices by their equal angles:
- in triangle corresponds to in triangle (both have angle ).
- corresponds to (they share the vertical angle at ).
- corresponds to (the remaining vertices).
So the corresponding sides are:
- ↔
- ↔
- ↔
Use the sides around the angles to make a proportion:
Substitute the known values:
Solve the proportion for SN
Solve
by cross-multiplying:
Now divide both sides by :
Simplify the fraction:
- , so
So the length of is .