Question 68·Medium·Systems of Two Linear Equations in Two Variables
The system of equations is
The solution to the system is . What is the value of ?
For SAT problems where you are given a system of two linear equations and asked for the value of an expression in and , first decide whether substitution or elimination will get you and fastest; elimination is often quicker when coefficients line up or are easy to make match. Solve the system efficiently, then plug the resulting and into the requested expression, being very careful with signs and the order of subtraction, since many wrong answers come from turning a minus into a plus or reversing the terms.
Hints
Focus on the system first
Before worrying about , think about how you normally solve for and in a system of two linear equations.
Pick a solving method
Would substitution or elimination be faster here? Look at the coefficients of and in the two equations and decide which method makes it easier to eliminate one variable.
Use your solution to find the expression
Once you know and , plug those values into the expression and simplify carefully. Pay close attention to the minus sign.
Desmos Guide
Graph the system
In Desmos, type the two equations exactly as they are:
4x - y = 7x + 2y = 4Desmos will display two lines on the coordinate plane.
Find the intersection point
Click on the point where the two lines intersect. Desmos will show the coordinates of this point; these are the values of and that solve the system.
Compute the value of the expression
Take the and coordinates from the intersection and type a new line in Desmos like 2*(x_value) - (y_value) using those numbers. The single number Desmos outputs is the value of for the system’s solution.
Step-by-step Explanation
Choose a method to solve the system
We have the system
To find and , we can use substitution or elimination. Here, elimination is convenient because we can quickly eliminate by combining the equations.
Eliminate one variable and solve for x and y
Multiply the second equation by so the coefficient of matches more closely with the first equation:
Now add this to the original first equation:
To solve more directly, another clean approach is to eliminate by making the coefficients opposites:
Multiply the first equation by :
Now add this to the original second equation:
Substitute back into one of the original equations, for example :
So the solution to the system is .
Evaluate the expression using the solution
We are asked for the value of .
Substitute and into :
So, the value of is 3.