Question 61·Easy·Systems of Two Linear Equations in Two Variables
The system of equations is
The solution to the system is . What is the value of ?
For systems where one equation already gives you a variable (like ), use substitution immediately: plug that value into the other equation so you have a single-variable equation. Then solve step by step, watching signs carefully. This is usually faster and less error-prone than graphing or trying to combine the equations using elimination on simple SAT questions like this.
Hints
Start with the easier equation
One of the equations already gives you directly. Use that first before working with the other equation.
Substitute for x
Take the value of from the second equation and plug it into so that the only variable left is .
Isolate y carefully
After substituting, simplify the multiplication, then use inverse operations (adding or subtracting on both sides, then dividing or multiplying if needed) to get alone. Pay close attention to negative signs.
Desmos Guide
Enter the equations in Desmos
Type the first equation in Desmos as y = 3x - 5 (this is just rewriting by solving for ). Then type the second equation as x = 4.
Find the intersection point
Look at the graph and find the point where the line y = 3x - 5 intersects the vertical line x = 4. The -coordinate of this intersection point is the value of in the solution .
Step-by-step Explanation
Use the simpler equation
From the second equation, we already know the exact value of :
This value must be used in the first equation to find .
Substitute into the first equation
Take and plug it into the first equation :
Now simplify .
Solve for
First compute :
Subtract 12 from both sides:
Multiply both sides by :
So the value of in the solution is .