Question 107·Medium·Systems of Two Linear Equations in Two Variables
The system of equations is
The solution to the system is . What is the value of ?
For systems of two linear equations where one is already solved for a variable (like ), substitution is usually the fastest: plug the expression for into the other equation, solve the resulting one-variable equation, then substitute back to find the second variable. Finally, carefully compute the requested expression (here, ), watching the order of operations and signs so you don’t confuse it with . This step-by-step approach minimizes errors and is quick enough for SAT timing.
Hints
Use substitution
You already know in terms of from the first equation. How can you use that to rewrite the second equation using only ?
Solve the resulting one-variable equation
After substituting into , simplify carefully and solve for step by step.
Don’t stop at finding
Once you have and , be sure to compute , not . Pay attention to the order of subtraction.
Desmos Guide
Enter both equations in Desmos
In Desmos, type y = 2x + 1 on one line. On another line, rewrite the second equation in -form: becomes y = 4x - 5, and type that as well.
Find the intersection point
Look at the graph and identify the point where the two lines intersect. Click that intersection point to see its coordinates .
Compute using Desmos
In a new expression line, type y - x using the and values from the intersection point (or directly type y1(x_intersect) - x_intersect if you labeled functions). Read the resulting numerical value; that is the value of .
Step-by-step Explanation
Substitute using the first equation
We are given the system:
Since , substitute for in the second equation:
becomes .
Solve for
Simplify the equation :
2x - 1 = 5
2x = 6
x = 3
Find the corresponding value
Use the first equation and plug in :
So the solution to the system is .
Compute
We are asked for .
Using :
So the correct answer is 4.