Once you know the slope $m$, plug it into $y = mx + b$ and substitute one of the points (for example, $(4, -2)$) to solve for $b$, the y-intercept.

After you find a candidate equation, substitute the other point $(10, 0)$ into it. The correct equation must work for both points.

In Desmos, type each option as its own equation line: y = 3x - 10, y = (1/3)x + 10/3, y = 3x + 10, and y = (1/3)x - 10/3. You will see four different lines on the coordinate plane.

On new lines, type (4, -2) and (10, 0) to plot these as points. Two dots should appear on the graph at those coordinates.

Look at the four lines and see which one passes exactly through both plotted points (4, -2) and (10, 0). The equation of that line is the correct answer choice.

Use the slope formula $m = \frac{y_2 - y_1}{x_2 - x_1}$ with the two given points.

Take $(x_1, y_1) = (4, -2)$ and $(x_2, y_2) = (10, 0)$, so $m = \frac{0 - (-2)}{10 - 4} = \frac{2}{6} = \frac{1}{3}$.

So the line’s slope is $\frac{1}{3}$.

Start with slope-intercept form $y = mx + b$, using $m = \frac{1}{3}$.

Substitute the point $(4, -2)$ into the equation: $-2 = \frac{1}{3}\cdot 4 + b$, so $-2 = \frac{4}{3} + b$.

Solve for $b$: $b = -2 - \frac{4}{3} = -\frac{10}{3}$. Thus the y-intercept is $-\frac{10}{3}$.

Substitute $m = \frac{1}{3}$ and $b = -\frac{10}{3}$ into $y = mx + b$ to get the line’s equation: $y = \frac{1}{3}x - \frac{10}{3}$.

Check with the other point $(10, 0)$: $\frac{1}{3}\cdot 10 - \frac{10}{3} = \frac{10}{3} - \frac{10}{3} = 0$, so $(10, 0)$ lies on this line as well.

Therefore, the correct answer is $y = \frac{1}{3}x - \frac{10}{3}$, which corresponds to choice D.