Write one expression for the number of large jars and one for the number of small jars, then multiply each by its price to get revenue from that type.

Once you have expressions for money from large jars and small jars, add them together and set this sum equal to $284.

For each answer choice, type its left-hand side minus 284 into Desmos, for example for one option type something like y = 10l + 6(2l - 4) - 284, using x instead of l if needed (e.g., y = 10x + 6(2x - 4) - 284). Do this separately for each choice.

For each graph, look for the x-intercept (where the graph crosses the x-axis). This x-value is the solution for that equation. You can tap/click on the x-intercept to see its coordinates.

For each equation, take its solution value for $l$, compute the number of small jars $2l - 4$, and then check that the total money $10l + 6(2l - 4)$ actually equals 284. The option whose equation produces a consistent, real-world solution (nonnegative jar counts and total revenue of 284) is the correct one.

The problem tells you that $l$ is the number of large jars.

She sells "4 fewer small jars than twice the number $l$ of large jars."

• Twice the number of large jars is $2l$.
• "4 fewer" than that means you subtract 4: the number of small jars is $2l - 4$.

Each large jar costs $10, and she sells $l$ large jars.

• Money from large jars: $10l$.

Each small jar costs $6, and she sells $2l - 4$ small jars.

• Money from small jars: $6(2l - 4)$.

Her total revenue from all jars is the sum of the money from large jars and from small jars.

So:

• Total revenue = (money from large jars) + (money from small jars)
• The problem says this total equals $284.

Putting all the pieces together:

• Money from large jars: $10l$
• Money from small jars: $6(2l - 4)$
• Total revenue: $284$

So the equation that could be used to find $l$ is