At one intercept, the graph touches the x-axis and turns back up instead of crossing. That tells you the corresponding factor is squared.

After you build the factored form with an unknown constant multiplier, plug in the labeled point on the graph to find that constant.

Type

$y=a(x+2)^2(x-1)(x-4)$

and let Desmos create the slider $a$.

Plot the point $(0,2)$. Adjust the slider $a$ until the graph passes through that point.

With that $a$, either evaluate $a(3+2)^2(3-1)(3-4)$ in a new expression line or make a table for the function and look at the y-value when $x=3$. Then match the result to the answer choices.

From the graph, the x-intercepts are at $x=-2$, $x=1$, and $x=4$.

At $x=-2$, the graph touches the x-axis and turns around, so $(x+2)$ is a repeated factor.

So, with least possible degree,

for some constant $a$.

The graph shows that $(0,2)$ lies on $f$, so $f(0)=2$.

Substitute $x=0$:

So $a=\frac{1}{8}$.

Now substitute $x=3$:

Therefore, the value of $f(3)$ is $-\frac{25}{4}$.