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Question 123·Hard·Nonlinear Functions

A ball is launched straight upward. Its height relative to the ground, in meters (negative values indicate below ground), is modeled by the function

h(t)=120(t18)(t2+4t45), h(t)= -\tfrac{1}{20}\,(t-18)\bigl(t^2+4t-45\bigr),

where tt is the time, in seconds, after the ball is launched.

How many seconds after the ball is launched does it first reach the ground?