The graph of a quadratic function is shown. The graph crosses the -axis at and . Which choice is the value of ?

Solution available with step-by-step explanation

SAT Nonlinear Functions Question 106 | Free SAT Prep | Aniko

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Question 106·Easy·Nonlinear Functions

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The graph of a quadratic function is shown. The graph crosses the $x$ -axis at $(a,0)$ and $(b,0)$ . Which choice is the value of $a+b$ ?

For quadratic graphs, $x$ -intercepts are read directly where the curve crosses the $x$ -axis. Once you have the two $x$ -values, the problem is just one arithmetic step: add them to find $a+b$ and match the result to a choice.

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Locate where $y=0$

The $x$ -intercepts are the points where the graph crosses the $x$ -axis.

Read the two $x$ -values

Use the grid to read the two $x$ -coordinates where the curve crosses the $x$ -axis.

Add the two values

Add the two $x$ -coordinates you found to get $a+b$ .

Desmos Guide

Record the intercept $x$ -values

From the given graph, identify the two points where the parabola crosses the $x$ -axis (where $y=0$ ) and record their $x$ -coordinates.

Add them in Desmos and match a choice

In Desmos, type the sum of the two recorded $x$ -values to compute $a+b$ . The result is $4$ , so select $4$ .

Step-by-step Explanation

Read the $x$ -intercepts

From the graph, the parabola crosses the $x$ -axis at $(-2,0)$ and $(6,0)$ , so $a=-2$ and $b=6$ .

Add the intercepts

Compute $a+b=-2+6=4$ , so the correct choice is $4$ .

Strategy

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Desmos Guide

Step-by-step Explanation

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Strategy

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Desmos Guide

Step-by-step Explanation