Question 7·Easy·Nonlinear Equations in One Variable; Systems in Two Variables
Solve for the positive value of in the equation
For quadratic equations like this on the SAT, first move everything to one side to get standard form . Then quickly check if the quadratic factors into two simple binomials by finding two numbers that multiply to and add to . Use the zero product property to get the possible solutions, and finally apply any extra conditions in the question (such as "positive value") to choose the correct one from the answer choices.
Hints
Get a standard quadratic form
Try to get all terms on one side so that the equation is equal to . What do you add or subtract from both sides to do this?
Factor the quadratic expression
Once you have , think of two numbers that multiply to and add up to .
Use the factors to solve for n
After factoring, use the fact that if a product is , then at least one factor must be . This will give you two possible values for ; decide which one fits the condition in the question.
Desmos Guide
Graph the related quadratic
In Desmos, type y = x^2 + 2x - 48. This represents the equation after moving all terms to one side.
Find the x-intercepts
Look for the points where the graph crosses the x-axis (where ). Note both x-values; these are the solutions to the equation, and the positive x-value is the one the question is asking for.
Step-by-step Explanation
Move all terms to one side
Start with the equation
To solve a quadratic equation, first set it equal to by subtracting from both sides:
Factor the quadratic
We want to factor into .
Look for two numbers that:
- multiply to (the constant term), and
- add to (the coefficient of ).
Those two numbers are and , so the factored form is
Use the zero product property and pick the positive solution
If a product of two factors is zero, then at least one factor must be zero. So set each factor equal to zero:
Solving these gives two values of , one negative and one positive. The problem asks for the positive value of , which is , so the correct answer choice is C.