If $(x - 6)(x + 1)(x - 2) = 0$, what can you say about $x - 6$, $x + 1$, or $x - 2$? What equations can you write from this?

After you find all the $x$-values that make any factor equal 0, focus only on the positive ones. Among those, which is the smallest?

In Desmos, type y = (x - 6)(x + 1)(x - 2) to graph the function that corresponds to the equation.

Look for the points where the graph crosses the x-axis (where $y = 0$). Tap or click on each x-intercept to see its x-value; these x-values are the solutions of the equation.

Among the x-intercepts that have positive x-values, identify which one is smallest. That x-value is the least positive solution and matches one of the answer choices.

The equation $(x - 6)(x + 1)(x - 2) = 0$ is written as a product of three factors equal to 0. When a product equals 0, at least one factor must be 0. So we set each factor equal to 0:

• $x - 6 = 0$
• $x + 1 = 0$
• $x - 2 = 0$

Solve each of the three equations:

• From $x - 6 = 0$, add 6 to both sides to get $x = 6$.
• From $x + 1 = 0$, subtract 1 from both sides to get $x = -1$.
• From $x - 2 = 0$, add 2 to both sides to get $x = 2$.

These are all the solutions of the original equation.

The solutions are $x = -1$, $x = 2$, and $x = 6$. Among these, the positive solutions are $2$ and $6$, and the least (smallest) positive one is $2$. So the correct answer choice is B) 2.