A quadratic equation has an term, so it can have two solutions even when the question asks for one. Graph the left side to see where it equals , then use a Desmos regression restricted to positive values to find the requested solution. Positive describes the solution's sign; it doesn't mean you can remove a minus sign from a negative solution.
Hints
- Hint 1
A root is an -value that makes the equation equal . On a graph of the left side, roots appear where the curve crosses the -axis. Which crossing has a positive -value?
- Hint 2
A Desmos regression can find an unknown number: replace with and with . A quadratic may have two roots, so add a restriction that keeps only positive values.
Step-by-step
Approach 1: Graph the roots, then restrict a Desmos regression
Step 1Locate the positive root
Type . Desmos draws a curve crossing the -axis on both sides of . An x-intercept is a crossing where , so each crossing's -value solves the equation. The right-hand crossing has a positive -value.
- Step 2
Find that root in Desmos
Add . In this regression, is the number Desmos finds, tells it to match the two sides, and the braces allow only positive values. Under PARAMETERS, Desmos shows . So the positive solution is . Grid in 3.
Approach 2: Factor to see why the roots differ
Step 1Split the middle term
To factor is to rewrite an expression as a product. Multiply the first and last coefficients: . The numbers and multiply to and add to , so split using them:
- Step 2
Factor the two groups
Take out of the first two terms and out of the last two. Both groups then have the same two-term expression:
- Step 3
Make one product
The common factor appears in both groups. Take that shared factor out:
- Step 4
Set each factor equal to zero
Use the zero-product property: if two numbers multiply to , at least one is . So set each whole factor equal to :
- Step 5
Rule out the negative root
For positive , both and are positive, so cannot equal . The positive solution must instead satisfy
- Step 6
Solve the remaining equation
Add to both sides: . This is positive, so it is the solution the question asks for. Grid in 3.