A line and a circle form a nonlinear system: a point solves the system only if it lies on both graphs. Type each equation into Desmos and click every intersection before comparing x-coordinates. A line can cross a circle twice, so the first point you find may have the smaller x-coordinate.
Hints
- Hint 1
A solution to a system makes both equations true. Graph the line first. Since its equation is , what must be true about the two coordinates of every point on it?
- Hint 2
Add the circle equation without rearranging it. Each place it crosses the line is a solution. Click both intersections, then compare the first numbers in their coordinate pairs.
Step-by-step
Approach 1: Graph the two equations
Step 1Graph the line
Type . Desmos draws a diagonal line. Every point on it has equal - and -coordinates, so a solution to this system must look like .
- Step 2
Read both intersections
Add as written. Desmos draws a circle crossing the line twice. Click both intersections to see and . Each intersection solves both equations, but you must compare the coordinate the question asks for. The first coordinates are and , so the greatest possible value of is . Choice C.
Approach 2: Substitute and factor
Step 1Use the line to eliminate y
The line says , so use substitution: replace with in the circle equation. This keeps only points that can lie on both graphs:
- Step 2
Expand the squares
Expand both squares, keeping their negative middle terms:
- Step 3
Combine like terms
Combine like terms, which are terms with the same power of :
- Step 4
Subtract 37 from both sides
Subtract from both sides:
- Step 5
Divide every term by 2
Divide every term by :
- Step 6
Factor the quadratic
To factor , find two numbers that multiply to and add to . They are and , so:
- Step 7
Set each factor to zero
By the zero-product rule, if a product is , at least one factor is . Set each factor to :
- Step 8
Compare both possible values
Solve each equation:
The greater possible value of is . Choice C.