Question 69·Hard·Equivalent Expressions
Let be a constant such that the polynomial
is divisible by . Which of the following expressions is equivalent to the polynomial for that value of ?
For questions that say a polynomial is divisible by , immediately use the Factor Theorem: plug in and set the result equal to to solve for any unknown constants. After finding those constants, rewrite the full polynomial and factor it by dividing by (synthetic division is usually fastest). Then match the resulting factors to the answer choices rather than expanding every option, which saves time and avoids unnecessary algebra.
Hints
Interpret "divisible by "
Think about what it means for a polynomial to be divisible by . How can you use a specific value of to test divisibility by ?
Plug in the right value of
Let . What should equal if is a factor, and what equation does that give you for ?
Use the value of to factor
After you find , substitute it back into to get a specific cubic. Then, since you know is a factor, divide by to find the quadratic factor and compare with the answer choices.
Desmos Guide
Graph the original polynomial with your value of
After you find algebraically, type the function into Desmos, for example: f(x) = 4x^3 - 27x^2 - 9x + 162 (use your specific value of ). This is the original polynomial that should be equal to one of the answer choice expressions for all .
Graph each answer choice as a separate function
Enter each option as its own function, such as g1(x) = (x - 3)(4x^2 - 15x + 54), g2(x) = (x - 3)(4x^2 + 15x - 54), etc. Compare their graphs to the graph of . The correct choice will have a graph that completely overlaps for every .
Use a difference function to confirm equivalence
To be precise, for each choice define a difference, like d1(x) = f(x) - g1(x). The correct answer’s difference function will appear as a horizontal line at for all , showing the two expressions are identical polynomials.
Step-by-step Explanation
Use divisibility by (Factor Theorem) to find
If a polynomial is divisible by , then .
Let
Substitute :
Compute the numbers:
- , so .
- , so .
- .
So
Because the polynomial is divisible by , we must have
Solve for and rewrite the polynomial
Solve the equation from Step 1:
Now substitute back into the polynomial:
Compute the constant term:
so the polynomial becomes
We now need to factor this polynomial, knowing it has a factor of . The other factor will be a quadratic of the form .
Divide by to find the quadratic factor and match the choice
Use synthetic division (or long division) to divide by .
Set up synthetic division with root and coefficients :
- Bring down .
- Multiply by to get ; add to to get .
- Multiply by to get ; add to to get .
- Multiply by to get ; add to to get (remainder , as expected).
So the quotient is
Therefore,
which matches answer choice D: .