Question 219·Hard·Equivalent Expressions
The polynomial is divisible by and leaves a remainder of when divided by . What is the value of ?
For polynomial remainder questions, immediately apply the Remainder Theorem: replace with the value that makes each divisor zero to get equations involving the unknown coefficients. Turn each condition (like “divisible by ” or “remainder when divided by ”) into an equation using and , then simplify to a small linear system in and . Solve the system quickly using elimination, and finally plug the values into the specific expression the question asks for (here, ), double-checking signs to avoid simple arithmetic errors.
Hints
Connect divisibility and remainders to function values
Recall the Remainder Theorem: when a polynomial is divided by , the remainder is . If the polynomial is divisible by , the remainder is , so .
Write equations for and
First, use the fact that the polynomial is divisible by to find an equation involving and . Then, use the given remainder when dividing by to form a second equation.
Solve the system efficiently
After you have the two equations in and , choose elimination or substitution to solve the system. Once you find and , be careful to compute , not or just or .
Desmos Guide
Represent the system in Desmos
In Desmos, use for and for . Enter the two equations as
2x - y = -63x + y = -17These are two lines whose intersection gives .
Find and from the intersection
Tap the point where the two lines intersect; Desmos will show its coordinates . These are the values of and .
Compute in Desmos
In a new expression line, type x - y and then substitute the intersection’s and values (or define parameters for and using those values). The resulting value shown by Desmos is the required .
Step-by-step Explanation
Use divisibility by (remainder 0)
If a polynomial is divisible by , then is a root and (this is the Remainder Theorem).
Here .
Compute :
Set this equal to :
Divide by to simplify:
so
Use remainder when divided by
When a polynomial is divided by , the remainder is .
We are told this remainder is , so .
Compute :
Set this equal to :
Subtract from both sides:
Divide by to simplify:
Solve the system of equations for and
Now solve the system:
Add the two equations to eliminate :
so
Substitute into :
Add to both sides. Since ,
so
Compute
We now have
Compute :
So the value of is . This corresponds to choice D.