Question 198·Hard·Equivalent Expressions
The equation above is true for all , where and are constants. What is the value of ?
For partial-fraction-style equivalence questions, start by factoring the denominator and multiplying through to clear fractions so you get a simple polynomial identity. Then use smart substitutions: pick values of that zero out one term at a time (like the roots of the denominator factors) to solve quickly for the unknown constants without heavy algebra. Finally, pay attention to what the question actually asks for (here, the product ) so you do not stop after finding just and .
Hints
Rewrite the denominator
Look at the denominator . Can you factor this quadratic into two binomials of the form ?
Clear the fractions
Once you factor the denominator as , multiply both sides of the equation by so that you are working with a simpler polynomial equation instead of fractions.
Choose smart x-values
After you have an equation like , try plugging in values of that make one of the terms on the right side equal to zero (think about and ). This will let you solve quickly for and .
Finish with the product
Once you know and , remember that the question asks for , not or separately. Multiply your two values together at the end.
Desmos Guide
Graph both sides with sliders for A and B
In Desmos, enter the left side as
y1 = (2x - 7) / (x^2 - 5x + 6)
Then enter the right side as
y2 = A / (x - 2) + B / (x - 3)
Desmos will create sliders for and .
Match the graphs to determine A and B
Adjust the sliders for and until the graph of exactly overlaps the graph of (away from and , where the function is undefined). When the two graphs coincide everywhere else, note the values of and shown on the sliders.
Find AB from the slider values
Take the and values you read from the sliders and multiply them (you can type A*B into Desmos or calculate it yourself). The resulting number is the value of you should choose in the answer options.
Step-by-step Explanation
Factor the denominator and clear the fractions
First factor the quadratic denominator.
The denominator is , which factors as .
Multiply both sides of the original equation by to remove the fractions:
Now you have a polynomial equation that must hold for all .
Use convenient x-values to find A and B
Because the equation
is true for all , you can choose values of that make one term on the right-hand side disappear.
-
Let :
- Left side: .
- Right side: .
- So , which gives .
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Let :
- Left side: .
- Right side: .
- So , which gives .
Now you know the specific values of and .
Compute the product AB
You found that and .
Now multiply them to get :
So, the value of is . This corresponds to choice B.