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Question 135·Hard·Equivalent Expressions

ax5+bx+4=3x+7(x5)(x+4)\frac{a}{x-5}+\frac{b}{x+4}=\frac{3x+7}{(x-5)(x+4)}

The equation above is true for all x5,4x\ne5,-4, where aa and bb are positive constants. What is the value of abab?