After distributing, you will have a linear equation in the form $10p - 15 = q$. What operation will undo the $-15$ so that $10p$ is by itself?

Once you have $10p$ on one side, how do you get $p$ alone? After that, try rewriting $\dfrac{q+15}{10}$ as a sum of two simpler fractions.

In Desmos, type y = 5(2x - 3). This shows the relationship between $q$ (on the y-axis) and $p$ (on the x-axis).

Add a horizontal line y = q_value for any specific value of $q$. The x-coordinate of the intersection gives $p$ in terms of that $q$.

Compare the x-values you get for different $q$ values to the expressions in the answer choices. The correct choice will match the pattern $p = (q + 15)/10 = q/10 + 3/2$.

Start with the equation:

Distribute the 5 on the left side:

Isolate the term with $p$ by undoing the $-15$. Add 15 to both sides:

Now isolate $p$ by dividing both sides by 10:

Split the single fraction into a sum of two fractions:

Simplify $\dfrac{15}{10}$ by dividing numerator and denominator by 5:

So

The expression equivalent to $p$ in terms of $q$ is $\dfrac{q}{10}+\dfrac{3}{2}$, which corresponds to choice D.