Question 25·200 Super-Hard SAT Math Questions·Advanced Math
In the given system of equations, is a constant. The system has exactly one ordered-pair solution . Which choice could be the value of ?
For a two-variable system that is symmetric in and , first test whether switching the variables creates another solution. If the problem states that there is exactly one ordered-pair solution, symmetry often forces . Substitute that relationship into the nonlinear equation, solve for the possible coordinate values, and check which one is included among the choices.
Hints
Switch the variables
Consider what happens to both equations if you exchange and .
Use the unique-solution condition
If and must represent the same ordered pair, what relationship must hold between and ?
Substitute the relationship
Substitute the relationship between and into , then compare the possible values with the answer choices.
Desmos Guide
Graph the circle and the parameterized line
Enter x^2+y^2=50 and x+y=p in Desmos. Desmos will create a slider for .
Find a value of with one intersection
Adjust until the line touches the circle at exactly one point. One such slider value is positive, and another is negative.
Read the x-coordinate
Click the single intersection point and read its -coordinate. Compare the displayed coordinate with the answer choices.
Step-by-step Explanation
Use the symmetry of the system
Both equations are unchanged when and are switched. Therefore, if is a solution, then is also a solution.
Because the system has exactly one ordered-pair solution, these two ordered pairs must be the same. Thus,
Substitute into the nonlinear equation
Replace with in :
Therefore,
Confirm that a listed value can occur
For , the linear equation requires
When , substituting into the first equation gives
which simplifies to
So gives exactly one solution when . Among the choices, could be the value of .