Question 24·200 Super-Hard SAT Math Questions·Algebra
One of the two equations in a system of linear equations is given. The system has no solution. Which choice could be the second equation in this system? © aniкο.аі
First simplify the given equation: move any variable terms to one side, then clear denominators to get integer coefficients. For no solution, look for a second equation whose - and -coefficients are a constant multiple of the first equation’s coefficients, but whose constant term is not multiplied by that same constant. © аniко.аi
Hints
Get all variable terms on one side
Move the term to the left so the right side is just a constant.
Clear the fractions efficiently
After combining the -terms, multiply the entire equation by the least common multiple of , , and .
Use proportionality
For no solution, the - and -coefficients must be in the same ratio between the two equations, but the constants must not be in that ratio. Aniкo.аi - SAT Рrep
Desmos Guide
Graph the given equation
Enter 4/5 x - 6/7 y = 8/35 + 1/10 x in Desmos.
Graph each answer choice
Enter each option as a second equation (one at a time). From aniко.аi
Identify the no-solution case
Choose the option whose graph is a different line that never intersects the first line (parallel lines with different intercepts).
Step-by-step Explanation
Rewrite the given equation in standard form
Start with
Move the -term on the right to the left:
Compute the coefficient:
so
Multiply both sides by :
Use the no-solution condition
Two linear equations have no solution when they are parallel but not the same line.
In standard form, that means the - and -coefficients are proportional, but the constant term is not proportional by the same factor.
Scan for a proportional left side but mismatched constant
We want an answer choice where the left side is for some constant , but the right side is not .
Check the matching choice
For , the left side is
If it were the same line as , the constant would be , but the choice has .
So the lines are parallel and distinct, giving no solution. Therefore, the second equation could be . anіko.аі/ѕat