In a nonlinear system, the equations share the same and , but a product such as makes one graph curved. Enter both equations in Desmos and click their intersections; those shared points satisfy both conditions. Read the first coordinate when the question asks for , rather than treating the product as an -value.
Hints
- Hint 1
A system requires the same pair to make both equations true. Desmos can graph each equation exactly as written, even when one makes a curve. What would a point shared by the two graphs tell you?
- Hint 2
An intersection is where two graphs meet, so its coordinates satisfy both equations. Click each crossing and read the labeled points in order. Which coordinate gives the value the question asks for?
Step-by-step
Approach 1: Graph both equations
- Step 1
Graph the sum equation
Type exactly as given. Desmos draws a line; every point on it has coordinates that add to . You still need the product condition.
- Step 2
Graph the product equation
Add on the next line. Desmos draws a curve with two crossings of the line. At an intersection, where the graphs cross, both equations hold for the same . A point on only one graph won't work.
- Step 3
Read the possible x-values
Click both crossings. Desmos labels them and . The first coordinate of is , so can be or . The question asks for a possible value, and is listed. Choice B.
Approach 2: Match the sum and product mentally
- Step 1
Find a pair with the given product
No Desmos needed. The small numbers allow a direct check. A factor pair is two numbers that multiply to a given number. Since , the pair meets the product condition.
- Step 2
Check the sum
Check the other equation: . So satisfies both equations, and its -value is . You only need one possible value. Choice B.