In a conditional probability question, the selection rule limits who can be picked. For exactly one workshop, keep the two table cells where attendance is yes for one workshop and no for the other. Restrict the group first, then count the target inside it. Add the kept counts, then use Desmos to divide the target count by that sum. A full row includes people who attended both.
Hints
- Hint 1
The exactly one condition keeps people with one yes and one no. Which two cells of the table describe those people? Leave out the cells for both workshops and neither workshop.
- Hint 2
The sample space is everyone who could be selected. Add the two kept counts to find how many people are eligible, rather than using a row total or the total of 100.
- Hint 3
A conditional probability compares the target count with the eligible count. Within the eligible group, which cell represents someone who attended financial literacy?
Step-by-step
Keep the eligible cells
Step 1Identify who attended exactly one workshop
The condition is attendance at one workshop, not both. The table shows who attended financial literacy but not coding, and who attended coding but not financial literacy. The who attended both and the who attended neither do not qualify.
- Step 2
Count the eligible participants
The sample space, meaning everyone who could be selected, contains only those two cells. Type in Desmos; it shows eligible participants.
- Step 3
Find the probability within that group
A probability is the count you want divided by the count that could be picked. Financial literacy within this group is the in the financial-literacy-but-not-coding cell, not the entire row of . Type in Desmos; it shows about . Tap its fraction button to see . So the probability that the selected participant attended financial literacy is . Choice D.