Question 6·Hard·Lines, Angles, and Triangles
In triangle , side and side . Point lies on such that . A line through drawn parallel to intersects side at point . What is the length of ?
(Express the answer as an integer)
For SAT geometry problems where a line inside a triangle is drawn parallel to one side, immediately think of similar triangles. Identify which sides correspond, then use the given segment ratios on one side of the triangle to find the scale factor between the small and large triangles. Apply that scale factor directly to the corresponding side you’re asked about, setting up a simple proportion instead of trying to compute multiple individual segment lengths.
Hints
Use the parallel line
A line drawn through parallel to creates a smaller triangle inside triangle . What can you say about the relationship between triangle and triangle ?
Find the scale factor
Use the ratio to determine what fraction of the whole side the segment is.
Relate corresponding sides
Once you know the fraction , apply the same ratio to the side to find the corresponding side in the smaller triangle, which is .
Desmos Guide
Compute the similarity ratio and apply it
First, note from that is of , so the scale factor from triangle to triangle is . In Desmos, type (3/5)*20 and read the output; this value is the length of , which is the side in the smaller triangle corresponding to .
Step-by-step Explanation
Identify the similar triangles
Since is drawn through parallel to , angle at is common to both triangles and , and the angles at and are corresponding because of the parallel lines.
Therefore, triangle is similar to triangle .
Find the ratio of similarity using the sides on
We are told that point is on such that .
The whole side is split into parts for and parts for , so:
- Total parts on = parts.
- So is
This means the scale factor from triangle (large) to triangle (small) is .
Match corresponding sides
In the similar triangles:
- Side in the big triangle corresponds to in the smaller triangle.
- Side in the big triangle corresponds to in the smaller triangle (they are parallel).
So the ratio of similarity is
We already found , and we know .
Set up and solve the proportion for
Use the proportion with the known values:
Solve for by multiplying both sides by :
So, the length of is .