Question 5·Medium·Circles
In the -plane, the circle is defined by the equation
Which of the following gives the center of the circle and its radius?
For circle equations on the SAT, aim to quickly convert from general form to standard form by completing the square on the - and -terms. Group -terms and -terms, add the necessary constants to complete each square, and rewrite as binomial squares to read off and ; double-check signs (inside the parentheses are and ) and remember to take the square root of the constant on the right to get the radius, not the radius squared.
Hints
Compare with the standard circle form
Write down the standard form of a circle, . How can you change the given equation so it looks like this?
Group x-terms and y-terms
Rearrange the equation so -terms are together and -terms are together. What expressions do you get for the and parts before completing the square?
Complete the square carefully
For each grouped expression, take half of the coefficient of (or ), square it, and add that value inside the group and to the other side of the equation. After that, can you rewrite each trinomial as a squared binomial?
Interpret signs and the radius correctly
Once you have an equation like , remember: the center is (notice the sign change inside the parentheses), and the radius is , not .
Desmos Guide
Graph the given circle
In Desmos, enter the equation x^2 + y^2 - 6x + 8y + 9 = 0 as one expression so you can see the circle on the coordinate plane.
Overlay a standard-form circle with sliders
Add a new expression (x - h)^2 + (y - k)^2 = r^2 and create sliders for h, k, and r. Adjust the sliders until this circle exactly overlaps the original one. The values of h and k at that point give the center, and the value of r gives the radius.
Step-by-step Explanation
Recall the standard form of a circle and group like terms
The standard form of a circle’s equation is
where the center is and the radius is .
Start with the given equation and group -terms together and -terms together:
Reorder and group:
You will now complete the square for both the -group and the -group.
Complete the square for the x and y expressions
For each group, take half of the linear coefficient and square it:
- For : half of is , and .
- For : half of is , and .
Add these squares inside the groups, and also to the other side of the equation to keep it balanced.
Start from
Add and inside the parentheses and to the right side:
Simplify the right-hand side:
Now subtract from both sides to isolate the completed-square groups:
Next, rewrite each trinomial as a squared binomial and compare to standard form.
Rewrite in standard form and identify center and radius
Each completed-square trinomial factors as a binomial squared:
So the equation becomes
Compare this to the standard form :
- means .
- is the same as , so .
- , so .
Therefore, the correct choice is: The center is at and the radius is . This corresponds to answer choice D.