Question 91·Easy·Systems of Two Linear Equations in Two Variables
A system of equations is given.
What is the solution to the system of equations?
For systems of two linear equations on the SAT, quickly choose the method that makes the arithmetic easiest—often substitution when one equation is already solved (or easy to solve) for a variable, like . Solve that equation for one variable, substitute into the other equation, solve for the remaining variable, then plug back to find the second value. On multiple-choice questions, you can also check answers efficiently by plugging each pair into both equations and eliminating any choice that fails even one equation.
Hints
Use one equation to solve for a variable
Look at the simpler equation . How can you solve this equation for in terms of ?
Substitute into the other equation
Once you have written in terms of , replace in the other equation with that expression.
Solve step by step
After substituting, carefully combine like terms, solve for , and then plug that value back into to find . Match the you get to one of the answer choices.
Desmos Guide
Graph the first equation
Rewrite the first equation as and type y = 2x - 5 into Desmos to graph the first line.
Graph the second equation
Rewrite the second equation as and type y = 7 - x into Desmos to graph the second line.
Find the intersection point
Look at where the two lines intersect on the graph. The coordinates of this intersection give the pair that satisfies both equations; match that pair to one of the answer choices.
Step-by-step Explanation
Understand what the solution means
A solution to a system of equations must make both equations true at the same time.
We need values of and that satisfy:
Express one variable in terms of the other
Use the second equation to solve for in terms of :
From ,
Now we can substitute this expression for into the first equation.
Substitute and solve for x
Substitute into the first equation :
Simplify the left side:
Add 7 to both sides:
Divide both sides by 3:
Find y and write the ordered pair
Use in :
So the solution to the system is , which corresponds to answer choice D.