Question 76·Easy·Systems of Two Linear Equations in Two Variables
The system of equations is
What is the solution to the given system of equations?
For systems like this on the SAT, quickly scan for coefficients that are opposites (like and ). If you see them, use elimination: add or subtract the equations to cancel one variable, solve for the remaining variable, then substitute back to find the other. Finally, do a fast mental check that your ordered pair satisfies both equations to avoid trap answers that only work in one equation.
Hints
Look at how appears in both equations
In one equation you have and in the other you have . What happens to if you add the two equations together?
Try combining the equations
Add the left-hand sides and the right-hand sides of the two equations. Which variable disappears, and what equation in one variable do you get?
Once you know one variable, find the other
After you solve for , plug that value into either or to solve for .
Check your pair
Whichever ordered pair you find, make sure it makes both equations true, not just one of them.
Desmos Guide
Enter the two equations as lines
Type y = 10 - x for the first equation and y = x - 2 for the second equation. Desmos will graph both lines.
Find the intersection point
Click or tap where the two lines cross. Desmos will display the coordinates of this intersection. Those coordinates give the values of and that solve the system.
Step-by-step Explanation
Notice the structure of the system
The system is:
The coefficients of are and , which makes this system perfect for the elimination method: adding the equations will cancel out .
Add the two equations to eliminate
Add the left sides and the right sides of the equations:
On the left, and cancel:
Now solve for :
Keep this value of for the next step.
Substitute back to find
Use either original equation. Using :
Substitute :
Solve for :
Now you know both and .
State and check the solution
Write the solution as an ordered pair using the values you found:
Check in both equations:
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So the solution to the system is .