Try adding the two equations. What happens to the $y$-terms when you do this, and what new equation in terms of $x$ alone do you get?

After you find $x$, plug it into either $2x + y = 10$ or $3x - y = 5$ and solve the resulting one-step equation for $y$.

In Desmos, type each equation on its own line exactly as given: 2x + y = 10 and 3x - y = 5. Desmos will graph both lines.

Look for the point where the two lines cross. Tap or click that intersection; Desmos will display its coordinates in the form (x, y).

From the intersection coordinates shown by Desmos, note the $y$-value. That $y$-coordinate is the answer to the question.

You have a system of two linear equations:

Notice that the coefficients of $y$ are $1$ and $-1$. This makes the elimination method very convenient, because adding the equations will cancel out $y$ immediately.

Write the equations one above the other and add them term by term:

The $y$ and $-y$ cancel out, leaving a single equation with $x$ only.

You now have a simple equation:

Divide both sides by $5$:

Now that you know $x$, you can substitute back into one of the original equations to find $y$.

Use either original equation; for example, use $2x + y = 10$.

Substitute $x = 3$:

So

Subtract $6$ from both sides:

Therefore, the value of $y$ is $4$.