Pick the two labeled points on each line to find that line’s slope and equation.

Once you have both equations in the form $y=\dots$, set them equal and solve for $x$, then substitute back to get $y$.

From the labeled points, determine the equations $y=x+1$ and $y=-\frac{1}{2}x+3$, then type both equations into Desmos.

Click the point where the two lines intersect. Read the intersection’s coordinates from the label Desmos shows.

From the graph, one line passes through $(-2,-1)$ and $(4,5)$. Its slope is

So its equation is $y=x+1$ (since $-1=-2+b \Rightarrow b=1$).

The other line passes through $(-2,4)$ and $(4,1)$. Its slope is

So its equation is $y=-\frac{1}{2}x+3$ (since $4=1+ b \Rightarrow b=3$).

Set $x+1$ equal to $-\frac{1}{2}x+3$:

Substitute $x=\frac{4}{3}$ into $y=x+1$:

So the solution (intersection point) is $\left(\frac{4}{3},\frac{7}{3}\right)$.