Question 17·Medium·Systems of Two Linear Equations in Two Variables
At a farmers market, Mason buys 8 peaches and 6 nectarines for a total of $13.20. The price of a peach is $0.40 less than the price of a nectarine. Which system of equations can be used to determine , the price in dollars of one peach, and , the price in dollars of one nectarine?
For “write the system of equations” problems, always start by clearly labeling your variables, then look for two separate pieces of information: (1) a total, which usually becomes something like “number × price” terms added together equals a total amount, and (2) a comparison phrase such as “less than” or “more than,” which becomes the second equation. Pay close attention to the direction of phrases like “0.40 less than” (subtract from the larger quantity) and check that the coefficients in your cost equation match the quantities mentioned in the problem (here, 8 peaches and 6 nectarines). Finally, compare your derived equations to the choices to select the exact matching system.
Hints
Clarify what each variable represents
Make sure you know what and stand for. One is the price of a peach and the other is the price of a nectarine. Every equation should reflect those meanings correctly.
Use the total cost information
Think about how to represent the total cost of 8 peaches and 6 nectarines using and . What expression represents the cost of the peaches? What expression represents the cost of the nectarines? Set their sum equal to $13.20.
Interpret “$0.40 less than” carefully
Decide which fruit is more expensive. Then, remember: if one quantity is "0.40 less than" another, you subtract $0.40 from the larger one to get the smaller one. Write an equation reflecting that relationship between and .
Check both equations against the story
For each answer choice, ask: (1) Do the coefficients in the cost equation match 8 peaches and 6 nectarines? (2) Does the relationship equation correctly show the peach price being $0.40 less than the nectarine price?
Desmos Guide
Set up variables in Desmos
In Desmos, let represent (peach price) and represent (nectarine price). You will enter equations using and instead of and .
Graph the total cost equation
Type the total cost equation using your chosen variable names, for example: 8x + 6y = 13.20. This line represents all pairs where 8 peaches and 6 nectarines cost $13.20.
Test each answer choice’s relationship equation
For each answer choice, convert its first equation to and (for example, y = x - 0.40 if it says ) and type it into Desmos. Look at the intersection point of this line with the cost line from step 2, and check whether the coordinates satisfy the story: the -value should be exactly $0.40 less than the -value (peach cheaper than nectarine). Only the correct system will match that condition.
Step-by-step Explanation
Identify the variables and the two conditions
We are told is the price of one peach (in dollars) and is the price of one nectarine (in dollars).
The problem gives two separate pieces of information:
- A total cost for a purchase (8 peaches and 6 nectarines cost $13.20).
- A relationship between the prices (a peach is $0.40 less than a nectarine).
Each piece of information will become one equation in the system.
Write the total cost equation
Mason buys 8 peaches at dollars each and 6 nectarines at dollars each.
- Cost of peaches:
- Cost of nectarines:
- Total cost: $13.20
So the total cost equation is:
Any correct answer must include this equation, and the coefficients (8 and 6) must match the numbers of fruits.
Translate “$0.40 less than” into an equation
"The price of a peach is $0.40 less than the price of a nectarine" means the nectarine is more expensive.
- Start with the higher price (the nectarine, ).
- Subtract $0.40 to get the lower price (the peach, ).
So the relationship between the prices is:
This correctly expresses that the peach costs $0.40 less than the nectarine (peach price = nectarine price minus $0.40).
Combine the equations and match the answer choice
From the total cost and the price relationship, the system of equations is:
Comparing to the answer choices, this system matches choice D:
.