Question 133·Easy·Systems of Two Linear Equations in Two Variables
What is the solution to the given system of equations?
For systems of two linear equations with nice coefficients, quickly scan for an easy elimination: if adding or subtracting the equations cancels one variable (like the terms here), use that to get a one-variable equation, solve it, then substitute back into either original equation to find the other variable. Always verify that your final pair makes both original equations true; this is faster and less error-prone on the SAT than guessing or checking only one equation.
Hints
Look for an easy elimination
Compare the two equations: and . What happens to the terms if you add the equations together?
Reduce to one variable
After you combine the equations so that disappears, you should get an equation with only . How do you solve that equation for ?
Use substitution to find the second variable
Once you know , plug it into one of the original equations, such as , and solve that equation to find .
Desmos Guide
Graph the first equation
In Desmos, rewrite the first equation as and type y = 3x - 7 into the first expression line. This graphs the line for .
Graph the second equation
Type y = 5 - x into the next expression line. This graphs the line for .
Find the intersection point
Look for the point where the two lines cross. Tap or click on that intersection point; Desmos will display its coordinates. Those coordinates give the solution to the system.
Step-by-step Explanation
Write the system and choose a method
We are given the system:
Notice that if we add these two equations, the terms will cancel, so elimination (adding the equations) is a quick method.
Eliminate by adding the equations
Add the left sides and the right sides of the two equations:
- Left side:
- Right side:
So the system simplifies to a single equation in one variable: .
Solve for and then for (conceptually)
From , divide both sides by to get the value of .
Then take that value of and substitute it into the simpler equation .
Solve for by subtracting your value of from .
State the solution as an ordered pair
Dividing by gives .
Substitute into :
, so .
Therefore, the solution to the system is .