Question 13·Easy·Systems of Two Linear Equations in Two Variables
What is the solution to the system of equations?
For systems of two linear equations on the SAT, first check if elimination is easy: if one variable has opposite coefficients (like and ), add or subtract the equations to eliminate that variable quickly, then solve for the remaining one and substitute back. Always verify that your solution satisfies both equations. When answer choices are given as ordered pairs, you can also plug each pair into both equations and eliminate wrong options fast, but algebraic elimination is usually faster and more reliable under time pressure.
Hints
Choose a method
Look at the two equations and decide whether substitution or elimination will be quicker. Do you see any variables that can cancel if you add or subtract the equations?
Try eliminating a variable
Compare the terms in both equations: one is and the other is . What happens to if you add the two equations together?
Solve step by step
After you eliminate one variable and solve for the other, plug that value back into either original equation to find the remaining variable.
Check your result
Once you find a pair , substitute it into both original equations to make sure it works in each one.
Desmos Guide
Enter the first equation in Desmos
Rewrite the first equation in slope-intercept form as . In Desmos, type y = 2x - 7 to graph this line.
Enter the second equation in Desmos
Rewrite the second equation as . In Desmos, type y = 11 - x to graph the second line.
Locate the intersection point
Look at the graph where the two lines cross. Click on the intersection point; Desmos will display its coordinates. Those coordinates give the pair that solves the system.
Step-by-step Explanation
Write the system clearly
We are given the system
Our goal is to find the pair that makes both equations true at the same time.
Eliminate one variable by adding the equations
Notice that in the first equation we have and in the second equation we have . If we add the two equations, the terms will cancel out:
Now we can solve this simpler equation for .
Solve for
From , divide both sides by :
Now that we know , we will substitute this value into one of the original equations to find .
Substitute to find and state the solution
Use the second equation and substitute :
Subtract from both sides:
So the solution that makes both equations true is , which corresponds to answer choice A.