Question 117·Hard·Systems of Two Linear Equations in Two Variables
Solve the system of equations.
The solution to the system is . What is the value of ?
(Express the answer as an integer)
For systems with decimals, first multiply each equation by a power of 10 to clear the decimals and work with whole numbers, which reduces arithmetic mistakes and speeds you up. Then pick the variable whose coefficients are easiest to match (usually with small multipliers), use elimination to remove that variable, solve the resulting one-variable equation, and, if needed, substitute back to find the other variable. Always double-check the key arithmetic steps when combining equations and dividing to solve for the variable.
Hints
Make the numbers easier
The equations have decimals. What simple number can you multiply both equations by to turn all coefficients into whole numbers?
Choose a variable to eliminate
After clearing decimals, look at the coefficients of and in the two equations. Which variable has coefficients that can be turned into the same number with smaller multipliers?
Combine the equations
Once the coefficients of match in size but are opposite in sign, add or subtract the equations so that disappears. What equation in alone do you get?
Finish solving for
You will get an equation of the form . How do you isolate from there?
Desmos Guide
Enter the two equations
In Desmos, type each equation exactly as given, one per line: 0.2x - 0.5y = 2 and 1.5x + 0.3y = 6.9. Desmos will graph both lines and show their intersection point.
Locate the intersection
Tap or click on the point where the two lines intersect. Desmos will display the coordinates of this point .
Read off the required value
From the intersection coordinates, note the -coordinate. That value is the solution for in the system.
Step-by-step Explanation
Clear the decimals
Start with the system:
Multiply both equations by 10 to remove the decimals:
- First equation: becomes .
- Second equation: becomes .
Now work with:
Prepare to eliminate one variable
Choose a variable to eliminate; is convenient because the coefficients and can both be turned into .
- Multiply the first equation by :
- Multiply the second equation by :
Now you have:
Eliminate and form an equation in
Add the two new equations together to eliminate :
- Left side: .
- Right side: .
So you get a single-variable equation:
Solve for
Solve the equation by dividing both sides by :
So, the value of in the solution to the system is .