Question 112·Easy·Systems of Two Linear Equations in Two Variables
The system of equations is
The solution to the system is . What is the value of ?
For systems of equations where one equation already has a variable isolated (like x = 3y), use substitution to be efficient: substitute that expression into the other equation to get a single-variable equation, solve it, then plug back to find the other variable. Finally, double-check which variable the question asks for (x or y) so you report the correct one; you can quickly confirm your result by graphing both equations and checking their intersection point.
Hints
Decide which equation to start with
One of the equations already has x isolated. How can you use that to rewrite the other equation using only y?
Substitute for x
In the equation , replace with the expression given in the other equation. What new equation in terms of y do you get?
Solve for y first
After substituting, you should have an equation like something times y equals 12. Solve that for y.
Answer the question being asked
Once you know y, plug it back into . Be careful: the question asks for the value of x, not y.
Desmos Guide
Enter the equations
In Desmos, type the first equation as x + y = 12 on one line and the second equation as x = 3y on another line. Both lines should appear on the graph.
Locate the intersection point
Adjust the viewing window if needed so you can see where the two lines cross. Tap or click on the intersection point; Desmos will display its coordinates .
Read off the x-value
Look at the x-coordinate of the intersection point. That x-value is the solution to the system and the answer choice you should select.
Step-by-step Explanation
Use substitution to write an equation in one variable
You are given the system
Because the second equation says , substitute for in the first equation:
Solve for y
Combine like terms on the left side of
to get
Now divide both sides by 4:
Use the relationship between x and y
You know from the system that and from the previous step that .
Substitute into :
Find the value of x
Evaluate the product from the previous step:
So the value of is , which corresponds to choice C.