For each answer choice, substitute its $x$ and $y$ values into both inequalities.

Eliminate any option that fails either inequality, even if it satisfies the other one.

In Desmos, enter $3x+2y\le 180$ and $x+y\ge 60$.

If desired, also enter $x\ge 0$ and $y\ge 0$ since numbers of items can’t be negative.

Plot each answer choice as a point (for example, type $(40,20)$). The correct choice is the only point that lies in the overlap of the shaded regions.

Prep-time limit: $3x+2y\le 180$.

Minimum number of items: $x+y\ge 60$.

Check each choice in both inequalities:

• $(40,20)$: $3(40)+2(20)=160\le 180$ and $40+20=60\ge 60$ (works)
• $(50,20)$: $3(50)+2(20)=190>180$ (fails)
• $(30,25)$: $30+25=55<60$ (fails)
• $(20,70)$: $3(20)+2(70)=200>180$ (fails)

Therefore, the ordered pair that satisfies both conditions is $(40,20)$.