Once you have an inequality, first move the constant term ($15$) to the other side, then isolate $c$ by dividing by $7.5$.

Your inequality will tell you $c$ must be less than or equal to some number. Since you cannot attend a fraction of a class, what is the largest whole number of classes that fits that condition?

In a Desmos expression line, type (120-15)/7.5 and press Enter. The output is the maximum number of classes allowed by the budget (as a number, possibly with decimals). Since the number of classes must be a whole number, take the greatest whole number less than or equal to the value that Desmos shows.

Let $c$ represent the number of fitness classes the member attends in a month.

The total cost is:

• $15$ dollars for the monthly membership fee, plus
• $7.50$ dollars for each class, or $7.5c$ dollars.

Because the member wants to spend no more than $120$ dollars, write the inequality:

This inequality says the total cost must be less than or equal to $120$ dollars.

Solve the inequality step by step.

First subtract $15$ from both sides:

Now divide both sides by $7.5$ to solve for $c$:

This fraction is the maximum allowed number of classes (not yet simplified).

Now simplify $\dfrac{105}{7.5}$.

Notice that $7.5 = \dfrac{15}{2}$, so:

So the inequality becomes $c \le 14$. Since you cannot attend a fraction of a class, the greatest whole number of classes that does not exceed the budget is 14.