Each cookie makes $2. If $x$ is the number of additional cookies, how can you write an expression for the extra money earned? Set this greater than or equal to the amount still needed.

Your inequality should look like $2x \ge$ (some number). Solve this inequality for $x$ and remember $x$ must be a whole number of cookies.

From your inequality, pick the smallest whole number value of $x$ that makes the inequality true. That is the number of additional cookies needed.

In Desmos, type y = 2x + 34. This represents the total amount of money the bakery will have after selling $x$ additional cookies.

Type a second equation: y = 50. This is the goal line showing $50 in sales.

Look at where the line $y = 2x + 34$ reaches or goes above the line $y = 50$. Use a table (tap the gear icon and select "Table" for the first equation) and find the smallest $x$-value where the corresponding $y$-value is at least 50; that $x$ is the minimum number of additional cookies needed.

Let $x$ be the number of additional cookies the bakery still needs to sell.

Each cookie brings in $2, and the bakery already has $34 in sales, so the total money after selling $x$ more cookies is

They want at least $50, which means the total must be greater than or equal to 50:

Solve the inequality step by step.

First, subtract $34 from both sides to get the money still needed in terms of $x$:

Now divide both sides of $2x \ge 16$ by 2:

This means the bakery must sell at least 8 more cookies to reach its goal, so the minimum number of additional cookies it must sell is 8.