Question 72·Hard·Linear Functions
A recording engineer uses a linear calibration function that converts a dial setting to an output level.
The studio software reports an adjusted level defined by
In the -plane, the graph of is a line that passes through the points and .
Which choice gives an equation for ?
When is linear and a new function is built from shifted values like , rewrite as and simplify the expression for the new function completely. Then find the equation of the new (graphed or point-defined) line and match slope/intercept (or coefficients of and the constant term) to solve for and .
Hints
Find first
Use the two given points to find the slope of , then use one point to find its -intercept.
Let
Because is linear, write as and substitute and into that expression.
Compare coefficients
After simplifying , match the slope and intercept you get with the slope and intercept of the line through and .
Desmos Guide
Enter the line from the two points
In Desmos, enter the two points (0,3) and (4,27), then enter g(x)=6x+3 (or use the two-point slope calculation to confirm the equation).
Define a general linear
Enter f(x)=m x + b (Desmos will treat and as sliders).
Build the adjusted function from
Enter G(x)=2f(x+3)-f(x-1).
Solve for and using the given points on
Enter the equations G(0)=3 and G(4)=27. Desmos will display the values of and that satisfy both, then choose the matching equation for from the answer choices.
Step-by-step Explanation
Model as a linear function and simplify
Since is linear, let
Then
So the slope of is , and the -intercept of is .
Find the equation of from the given points
The line passes through and , so its slope is
Since , the -intercept is , so
Match the slope to find
From Step 1, has slope . From Step 2, has slope .
So
Match the intercept to find
From Step 1, the -intercept of is . From Step 2, the -intercept of is .
So
Substitute :
Therefore,