Question 52·Easy·Linear Functions
A printing company uses the function
to determine the total cost , in dollars, of producing custom coffee mugs. If the total cost is $300, how many mugs are produced?
For linear cost function problems, immediately plug the given total cost into the function, set up an equation, and solve step by step: first undo any added or subtracted constant (fixed cost), then undo the multiplication (per-item cost). Keep track of what the variable represents so you can interpret your final value in context and check that it is reasonable (for example, it should be a positive, whole number of items).
Hints
Use the cost function with the given total cost
You are told the total cost is $300. How can you use this information with the function ?
Set up an equation to solve for
Replace in the function with and write an equation with as the only variable. What equation do you get?
Isolate step by step
Once you have your equation, first undo the , then deal with the multiplied by . What operations should you use, in what order?
Remember what represents
After you solve for , think about what stands for in the context of the problem (number of mugs).
Desmos Guide
Enter the cost function
In Desmos, type y = 12x + 60 to graph the cost function.
Represent the $300 cost
On a new line, type y = 300 to graph a horizontal line showing a total cost of $300.
Find the number of mugs
Look for the intersection point of the two graphs. The x-coordinate of this intersection is the number of mugs produced when the cost is $300.
Step-by-step Explanation
Write the equation for this specific situation
You are told the total cost is $300, and the cost function is
So set equal to :
Now you just need to solve this equation for .
Isolate the term with
To get by itself, first remove the constant term from the right side.
Subtract from both sides:
Now the equation is simpler: .
Solve for and interpret the result
Now divide both sides of by to solve for :
Since is the number of mugs, the company produces 20 mugs when the total cost is $300.