Question 78·Hard·Linear Equations in Two Variables
In the -plane, line is defined by and line is defined by . The two lines intersect at point . Line is perpendicular to line and passes through point . Which of the following is an equation of line ?
For SAT questions about a line perpendicular to a given line and passing through an intersection point, work systematically: first solve the two given equations as a system to find the intersection point P. Next, rewrite the relevant line in slope-intercept form to read off its slope, then take the negative reciprocal to get the perpendicular slope. Use P and this slope in (or point-slope form) to find an equation for the new line, and finally rearrange into the form used in the answer choices (usually ). To save time, you can also quickly eliminate options whose slopes are not the negative reciprocal before checking which one passes through P.
Hints
Locate point P
To find the point where lines k and j intersect, substitute the expression for from into the equation and solve for , then for .
Think about slopes of perpendicular lines
Rewrite in the form to identify the slope of line k. How is the slope of a line perpendicular to this related to ?
Use point-slope or slope-intercept form
Once you know the slope of line m and the coordinates of point P, plug them into either point-slope form or into to get an equation for line m.
Match the form of the answer choices
After finding an equation for line m, rearrange it into the form with integer coefficients and compare it with the answer options.
Desmos Guide
Graph the given lines and find point P
Type 4x - 5y = 20 and y = -2x + 3 into Desmos. Tap on their intersection to see the coordinates of point ; this is the point through which line m must pass.
Identify the slope needed for line m
Either solve for (so you can see the slope ), or visually note that slope from the graph. Then take the negative reciprocal to find the slope that a perpendicular line must have; this is the slope that line m needs.
Test each answer choice in Desmos
Enter each option (for example, 10x + 8y = 9) into Desmos one at a time. For each, solve it for within Desmos or visually inspect the graph to check two things: (1) does the line’s slope match the perpendicular slope you found, and (2) does the line pass exactly through point from step 1?
Choose the matching equation
The correct choice is the one whose graph both has the perpendicular slope from step 2 and goes through point from step 1; read off which equation that is from the answer options.
Step-by-step Explanation
Find the intersection point P of lines k and j
Line k:
Line j:
Substitute into the equation for line k:
Simplify:
Now substitute into :
So the lines intersect at . This point lies on line m as well.
Find the slope of line k and the slope of a perpendicular line
Start with line k:
Solve for to get slope-intercept form.
Subtract from both sides:
Divide by :
The slope of line k is .
For a perpendicular line, the slope is the negative reciprocal: flip the fraction and change the sign.
So the slope of line m is . Line m must have slope and pass through .
Write an equation for line m using point and slope
Use slope-intercept form with .
Plug in the coordinates of point to solve for :
Compute the product:
So:
Write as :
Add to both sides:
Thus line m in slope-intercept form is:
Convert the equation of line m to standard form and match a choice
The answer choices are in standard form , with integer coefficients.
Start from the slope-intercept form of line m:
Clear the denominators by multiplying every term by 8:
Now move to the left side by adding to both sides:
This matches choice A), so the correct equation of line m is .